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Algebra
#8
Child, that's a system of equations, listen here.

Equation 2 is almost perfect for the Substitution method.

Subtract 2y from both said of that and you get x = -2y +4

Take that and replace it with the x in equation one; 2(-2y +4) - 3y = 8

Distributive property and solve for y; -4y - 3y + 8 = 8

y = 0

Take that and go to Equation 2; x + 2(0) = 4

Distribute and solve for x; x + 0 = 4

x = 4

Now put both back in equation 1 to check them

2(4) - 3(0) = 8

8 = 8 Therefore, correct

Kundral received Substitution Method *DO-DA-DO*

I'll post Elimination in a minute

EliminaTION!

Equation 2, yet again, is almost perfect for elimination

Multiply Equation 2 by -2 giving you -2x + 4y = -8

You know have that and Equation 1, add the two equations together and you knock out x y = 4

Take that y put it in equation 1, solve for x, take x and y put it in equation 2 to check your work

Kundral received EliminaTION Method *DO-DA-DO*
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Messages In This Thread
Algebra - by Kundral - 12-21-2008, 01:39 AM
RE: Algebra - by Crim - 12-21-2008, 04:16 AM
RE: Algebra - by Kundral - 12-21-2008, 06:11 AM
RE: Algebra - by Crim - 12-21-2008, 07:03 AM
RE: Algebra - by Kundral - 12-21-2008, 08:07 AM
RE: Algebra - by Erethzium - 12-21-2008, 03:09 PM
RE: Algebra - by Kundral - 12-21-2008, 04:33 PM
RE: Algebra - by Crim - 12-21-2008, 05:44 PM
RE: Algebra - by Bee - 12-21-2008, 06:36 PM
RE: Algebra - by DragonMasterX - 12-22-2008, 12:47 AM
RE: Algebra - by MagusKnight - 12-22-2008, 01:21 AM
RE: Algebra - by Kundral - 12-22-2008, 12:39 PM
RE: Algebra - by Crim - 12-23-2008, 08:10 AM
RE: Algebra - by Kundral - 12-23-2008, 02:10 PM